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    please help me!
    i want to know that how the formula for maximum channal capacity ( bits per seconds) is derived.

    c= max. channel capacity
    b= bandwidth
    v= no.of dicrete levels

    for noise less channel we know
    c= 2b(loghaving base 2)v

    for binary system v=2
    thus c= 2b
    means if channelbandwidth is 3000 hz ,then channal capacity is 6000bits/sec.

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Reply To: c=2*bandwidth????
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