Reverse Erlang This topic has 1 reply, 1 voice, and was last updated 23 years, 11 months ago by Marc. Viewing 2 posts - 1 through 2 (of 2 total) Author Posts 17th December 1999 at 16:41 #32491 ChidchanokGuest I’m doing my project on the topic of Teletraffic Model. I really want to how to calculate Erlang B Erlang C, Extended Erlang B in the recurcive way. Anyone can help me? 3rd January 2000 at 16:42 #32492 MarcGuest Hi, For Erlang B : E(N,Y) = [ (YexpN / N!) ] / [ (Sigma(j=0 to N) Yexpj / j!) ] with N in Erlangs, Y=nb of circuits. Recursive solution : E(N,Y) = [ (Y/N) * E(N-1,Y) ] / [ 1 + Y/N * E(N-1, Y) ] Hope this can help. Marc. Author Posts Viewing 2 posts - 1 through 2 (of 2 total) The forum ‘Telecom Design’ is closed to new topics and replies.