- This topic has 33 replies, 1 voice, and was last updated 16 years, 7 months ago by james.
29th August 2003 at 06:34 #35136M.SGuest
Via the BCCH the mobile station is informed about the system configuration parameters (for
example Local Area Identification, Cell Identity and Neighboring Cells). Using this information the
mobile station can choose the best cell to attach.3rd September 2003 at 08:11 #35137NavpreetGuest
I would like to know that, suppose we are having 4 TRX in one cell and SDCCH is 16 and in combine mode. How many TCH will be available and the other left out time slots for control Channels will be used by which no. of TRX , as we know one TRX carries 8 time slots.3rd September 2003 at 08:30 #35138NavpreetGuest
I would like to know that, suppose we are having 4 TRX in one cell and SDCCH is 16 and in combine mode. How many TCH will be available and the other left out time slots for control Channels will be used by which no. of TRX , as we know one TRX carries 8 time slots.4th September 2003 at 01:42 #35139NguyenGuest
If you want the control channel configuration is combined mode, the SDCCH number will be 12 or 20. The 16 SDCCH channels is the non-combined mode.
If the cell with 4 TRX (32 timeslots) and 16 SDCCH, the available TCH will be 29. All of these TCHs and SDCCHs will occupy 29 + (16/8) = 31 timeslots. The first timeslot of the first TRX in the cell will be used for (1 BCCH + 9 CCCH).
Brgds4th September 2003 at 06:29 #35140umreetGuest
How come the available TCH will be 29???
regards4th September 2003 at 07:43 #35141NguyenGuest
The total timeslots is 4×8=32. The number of SDCCH is 16 => occupied 16/8=2 timeslots. 16 SDCCH => non-combined configuration => need 1 timeslot for 1BCCH+9CCCH.
Hence the available timeslots for TCH is: 32-2-1=29.
ok?4th September 2003 at 07:54 #35142UmreetGuest
Yeah got it ! Thanx..
If the SDCCH is 12 .How many occupied?? is it 12/4=3
In this case it will be combined.Right?So no extra TS needed for BCCH+CCCH.
How many TS for TCH will occupied?
Is it 32-3=29(same)
Please correct me if i am wrong..
Regards4th September 2003 at 14:38 #35143PaulGuest
In that case, you would have 4 SDCCH combined and 8 non-combined, so there would be one timeslot BCCH/CCCH/4*SDCCH and one timeslot 8*SDCCH, leaving 30 TCH!5th September 2003 at 01:36 #35144NguyenGuest
Paul has given the correct answer for your question. TCH=30.
Brgds5th September 2003 at 06:09 #35145UmreetGuest
Thanx Nguyen and Paul..
Now i got the compelete thing….
Nguyen,while going through one of the thread on SDCCH,i do came to know about ur SDCCH dimensioning tool.I’ll b highly obliged if u cud send that tool to my mail ID.
My mail ID is:
I m new to this field and wants lots of info on channel dimensioning!
Thanx and Regards5th September 2003 at 17:22 #35146zulfiGuest
could somebody tell me abt some site to study hopping esp SFH.
mail me at firstname.lastname@example.org September 2003 at 03:23 #35147NIBU KOSHYGuest
please teach about synthesizer hopping using in gsm, which hutchison telecom industry uses.16th September 2003 at 10:35 #35148TrazyGuest
I would like to know that if I implement PBCCH in the network, what should I concern about.
Could anyone tell me the advantage and disadvantage of using PBCCH?
Thank you so much.16th September 2003 at 18:12 #35149osaro aigbedeGuest
i would like to get more information on BCCH and how to over come hopping9th November 2003 at 07:45 #35150NavpreetGuest
U said we have 4 TRX and having 32 timeslots and 16 SDCCH 32-2-1 =29. Ok , the subtracted 1 was for BCCH and 9 CCCH that will be in 1 timeslot of First TRX and now my question is, the 2 time slots we have subtracted above for SDDCH will be used in which no of Timeslots.