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QAM

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  • #44636 Reply
    Comm101011
    Guest

    If I have a Bitrate Rb=64kbit/s and a Bandwidth of B=24kHz,
    how many symbols do I have for QAM?
    And how do I design a receiver for it?

    #44637 Reply
    jood
    Guest

    H/B= log2 (1+ Eb/No * H/B)
    where:
    H/B=> bit rate/band width(spectral effieciency)
    Eb/No=> energy per bit/noise densiny.
    SO from obtained Eb/No you can find the required theoretical Rx for QAM.& by adding the extra noise yuo will get the real.
    # bit per symbol is constant= Nb=log2(M) = 4bit.

    #44638 Reply
    nicolaaa
    Guest

    Hello. I am planning to start writing my thesis about m-qam but i really did not find any basic informations about it so i would like you to explain me in easy way the meaning of MQAM systems performance , error probability evaluation, what is the basic information about them,i know something about them i need more simple.

    #44639 Reply
    paraHO
    Guest

    nicolaaa if I may be polite and say the first thing to do is identify title and then use the acronym.

    Multi-level Quadrature Amplitude Modulation (“M-QAM”).

    This is because in many instance people familar QoS etc in terms of 16-QAM and constellation relevant and even Quadrature Phase Shift Keying (“QPSK”).

    M-QAM deal with detection of modulated signals for use in radio communication.

    So help us with what it is you not understand please?

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