3rd December 2010 at 20:52
#64972
pix
Guest
el mariachi,
yes, that’s correct.
The real formula of “minute erl per drop” is “erlang*60 / number of drops”
(if measurements done in one hour)
my formula is just a trick, to study the real formula.
jack,
drop/erl = 0.64
FR traffic = 23.43 erl
HR traffic = 18.12 erl
–> drop = 0.64*(23.43+18.12) = 26.6 drops
with “my” stupid formula, you should get:
drop/calls = 26.6drops / [(23.43erl+18.12erl)*3600/13.43s] = 26.6/11138 = 0.2%
In your inputs, you say that there are only 2164 call attempts, but I find “11,138” tch attempts. I guess the difference is due to high amount of incoming HO in the cell.
Look at the very short tch duration avg… it’s very bad !! 13 seconds !!
regards
pix