hi,
yes, it will be half, in case 1.
each MS can use a PDCH in only 1 occurence out of 2.
It’s like half-rate.
Instead of having 100% of the 4 PDCH, which is 59.2*4 kbps, each MS gets only, in average, 59.2*4 / 2.
Regards
pix
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