14th September 2009 at 05:32
#58824
Guest
Hi Veer
I’ll give you an example to understand this.
1 erlang=1 TS busy for 1 hour.
Now,1 TS=64kBps,
So 1 erlang= 64kBps of payload for 1 hour.
This theory you have to apply for each & every coding scheme accordingly.
There is also an easier way around.
You just take mean no. of busy PDCH’s.