14th November 2008 at 08:45
#54623
Guest
Hi Yan,
Free space path loss=32.44+20Log(f)+20Log(d)
where f=Frequency,
d=distance between MS and BTS.
So,you can see from tha formula that,as f (Frequency) is higher,path loss will be higher.
So,at a same distance,1800 band should have lower coverage then 900 band due to higher path loss.