Ali,
Gotcha ! The full BSIC is included in the encrypted bits of the RACH :
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3GPP 45.003, chapter 4.6 & 4.8
The six bits of the BSIC, {B(0),B(1),…,B(5)}, of the BS to which the Random Access is intended, are added bitwise modulo 2 to the six parity bits, {p(0),p(1),…,p(5)}. This results in six colour bits, C(0) to C(5) defined as C(k) = b(k) + p(k) (k = 0 to 5) where:
b(0) = MSB of PLMN colour code
b(5) = LSB of BS colour code.
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Bijoy,
Friendly is good, don’t worry 🙂
I just get a little suspicious when someone is trying to drink me. Because first, you need to liquify me. Not a pleasant experience…