Pix,
U mean the 41 bits synchronization bits are actually Training sequence bits..then what does this 36 bits of access information in access burst do???
and one more thing..if by computing BTS asks MS to send the data in advance by say 3 bits(i.e 3*3.69micro second)is MS advancing the data 3slots(the diff bn rx and tx of MS)-(3*3.69)microsecond..