24th February 2006 at 19:33
#42941
RF Learner
Guest
Hi
1 watt = 30dBm
just add 3dBm if the power is doubled i.e
2 watt = 30 +3 = 33dBm
4 watt = 33 +3 = 36 dBm so on.
formula
P(dBm) = 10 log(w/10e-3)
take anti log of dBm, the result will b in watts.
Thanks