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Minute Erlang Per drop

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  • #64966 Reply

    Hi All Expert,

    Please Explain me What is Minute Erlang per drop.

    #64967 Reply

    Hi fresher
    It means the average Erlang mins carried between 2 successive call drops in the cell.


    #64968 Reply
    Fresh Opt

    and what is the importance of minuteErl/call drop? What tells us?
    Fresh Opt

    #64969 Reply

    hi fresh, fresher and freshest,

    it shows the “density” of drops in the cell. In the end, it is just another way to estimate the call drop rate in the cell.
    20 erlangs
    10 drops
    = 2 erl/drop = 120 minute-erl/drop

    There is 1 drop every 2 hours of communication in the cell.

    Now let’s assume that 1 call = 1 minute
    There are 20 erlangs, that’s 20 hours = 1,200 minutes = 1,200 calls
    CDR = 10/1,200 = 0.89%

    There is a proportional relationship between min-erl/drop and the call drop rate. You could as well use the following formula :
    drops / (erlang * 3600 / tch_average_duration [s])

    the main difference is that if TCH are shorter than usual (due to HO for example), it means there are more calls in the cell, but still the same amount of drops : you drop rate decreases.
    If TCH are longer than usual, the drop rate increases. But a “drop” KPI should not be impacted by TCH duration.

    Whereas the minute-erlang per drop remains stable whatever the duration of the TCH.
    It looks like the min-erlang per drop is a more objective approach than the call drop rate, especially in networks with a high amount of handovers. Problematic cells with high amount of HO have shorter TCH, therefore they have a better call drop rate than the subscribers are experiencing.

    Well, while writing this post I convinced myself that erl/drop is useful :)) I am a manipulative master….

    Regards 🙂

    #64970 Reply
    el mariachi

    hello Pix,
    drops / (erlang * 3600 / tch_average_duration [s])

    drops:number of drops
    erlang: TCH traffic carried
    tch_average_duration [s]: call duration

    please confirm

    #64971 Reply

    hi pix.
    i think that Drop/Erlang is more accurate for this case.

    any way,suppose this situation:
    TCH Traffic=23.4300003051757
    HTCH T raffic=18.1299991607666
    Defined Tch=Avail Tch=22
    Avail HTCH=43
    TCH MHT=13.43
    Call attempt TCH=2164

    NOTE:this measurement is done in 1 Houre.
    according your formula,what is number of drop calls in this 1 houre?

    #64972 Reply

    el mariachi,

    yes, that’s correct.
    The real formula of “minute erl per drop” is “erlang*60 / number of drops”
    (if measurements done in one hour)
    my formula is just a trick, to study the real formula.


    drop/erl = 0.64
    FR traffic = 23.43 erl
    HR traffic = 18.12 erl
    –> drop = 0.64*(23.43+18.12) = 26.6 drops

    with “my” stupid formula, you should get:
    drop/calls = 26.6drops / [(23.43erl+18.12erl)*3600/13.43s] = 26.6/11138 = 0.2%

    In your inputs, you say that there are only 2164 call attempts, but I find “11,138” tch attempts. I guess the difference is due to high amount of incoming HO in the cell.
    Look at the very short tch duration avg… it’s very bad !! 13 seconds !!


    #64973 Reply
    AK singh

    What Is Earlang per drop

    #64974 Reply

    yes, that’s the perfect title for what’s written below.
    thank you for your inputs.

    #64975 Reply

    what is the unit on TCH ERLANG PER MINUTE DROP??

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