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  • This topic has 7 replies, 1 voice, and was last updated 12 years ago by Hasan Murad.
Viewing 8 posts - 1 through 8 (of 8 total)
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  • #63874 Reply

    – min. E1 TS or E1 SubTS required in a site (3+3+3) to activate MCS9?
    – if we added extra or more than required will improve something?
    – if we had a site with 2+2+2 and one E1; what will be min. required E1 TS to keep all subs. with MSC9?
    – if I had a site with 4+4+4 with 1 E1 and just 2 idle TSs are defined; what dose that mean?
    hope I get answers with some justifications will be highly appreciated please


    #63875 Reply

    1) As we are using in our n/w, min 4 E1 subts needed for edge, it cant be increased more than 4, for gprs it 1 and for cs3/4 its 1.

    2)for 2/2/2 its 2.25*6=18 + 3, so 32 – 22= 10 so 2 edge channels + 1 gprs channel at max only if u are not using any HR, otherwise u will get E1 constraint.

    3)4/4/4 site , 2.25*112=27 , +3 for signaling, so 32-30=2 TS left on E1.

    1 trx take 2.25 on the E1 hence this calculation, hope it clears your question.

    #63876 Reply

    To increase more subts you need another E1 on the site

    #63877 Reply

    hiiii jack/tanuj

    if i have a configuration with 4+4+4.then can u tell me how many subcribers it can handle.

    #63878 Reply

    Thanks Tanuj;
    Your time really appreciated; just why you been taking 2.25 for each TRX? I saw some taking 128 Kbps and 16 Kbps for RSL and you toke 2.25 E1TS and 3 for signaling again? can you give us short Expl. please?


    #63879 Reply

    Hi Vikas,
    if you have 4/4/4 config, then supposing each cell has 1 SDCCH and SACH,FACH etc leaving 4TS free on BCCH and other trx have 8ts, then 8*3+4=28, the for 3 cells it becomes 28*3=84 calls. so at max 84 tch can be configured at Full rate so 84 subscribers but you may have to increase the SD count if its a busy site. i have not considered any pdtch configured on site

    #63880 Reply

    Hi Jack

    you have answered your question yourself,
    1 trx = 128kbps and rsl =16 kbps, 1 E1=2.048 mbps therefore 2.048/32=0.064 mbps = 64 kbps i.e. 1TS = 64kbps, so 128 kbps= 2TS + for rsl 16 kbps ie 0.25ts so total 1 trx=2.25.

    #63881 Reply
    Hasan Murad

    How can I will bee clear about the abis of the dual band 4+4+4 configaration

Viewing 8 posts - 1 through 8 (of 8 total)
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