 This topic has 13 replies, 1 voice, and was last updated 12 years ago by Deepak.

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19th August 2008 at 10:28 #53563somnath duttaGuest
With some IMSI value,CCCH_CONFIG=0,BS_AG_BLK_RES=1,BS_PA_MFRMS=4,how to calculate the actual paging group?I want the actual value of the paging group.Plz help.
20th August 2008 at 07:48 #53564GarryGuest32 paging groups with non combined and 8 with combined.
21st August 2008 at 07:09 #53565somnath duttaGuestNo I want the actual paging group which is assigned for me.That means how to calculate the actual paging group based on my IMSI/TMSI which is assigned to me.
23rd August 2008 at 21:07 #53566pixGuestthere’s a formula, that you can find in a 3GPP document.
http://www.3gpp.org25th August 2008 at 05:01 #53567somnathGuestActually I have tried to calculate the same using that formula…but there Im facing some prob where mod value is returning a ‘0’…which is meaningless…so I feel Im doing some mistake somewhere.So can you help?
25th August 2008 at 07:58 #53568pixGuestyes, but you’ll have to give me the formula, so i can give it a try. No time to look for the formula by myself, sorry…
27th August 2008 at 12:31 #53569somnathGuestpagging_group(0….N1)= (IMSI mod 1000)mod N
N=(no of CCCH group in a multiframeno of blk for AGCH)*no of multiframe between pagging
for instance no of CCCH blk available=9,AGCH blobked=1,
no of pagging between multiframe=4plz help
27th August 2008 at 13:22 #53570pixGuestIMSI mod 1000 –> gives you the 3 last digits of the IMSI
3 last digits mod 48 –> in excel, type the formula
“=MOD(3digits;48)”why 48 : because (91)x4 = 48
the result is the value of the paging group…
regards,
pix28th August 2008 at 05:16 #53571somnathGuestIt will be 32 instead of 48 because
(91)*4=3228th August 2008 at 08:28 #53572pixGuestwhat a shame… thx somnath, i’m doing really stupid mistakes sometimes ! :))
i was even wondering how come a “modulo 48” was used, while there is about 20 to 30 paging groups normally… never crossed my mind that 8×4 = 32.
16th May 2011 at 05:34 #53573anhGuestLet say, we have 100 IMSIs belonging to paging group No.2
With paging request type 3 (4 MS per paging msg), how will these 100 IMSIs be paged?Thanks,
16th May 2011 at 11:56 #53574pixGuesthi,
these Ms will be paged by their TMSI, if the MSC has allocated a TMSI to these MS, and if the “TMSI paging” method is defined in the MSC.If anyone has more info, welcome to share…
regards
pix16th August 2011 at 08:34 #53575MickGuestIn case of Paging Request Type the mobile stations are identified by their TMSIs (TS 04.08)
23rd August 2012 at 07:15 #53576DeepakGuestCCCHCONF Value tells,Whether you are using COMBINED or NONCOMBINED Configuration.
I dont remember exactly, What exactly CCCH_CONFIG=0 stands for.First lets Consider COMBINED config
COMBINED : Total CCCH = 9
BS_AG_BLK_RES=1
So Channels reserved for Pagig = 91 = 8BS_PA_MFRMS=4 : This tells After how many multiframes paging group repeats.
So total Paging groups = 8*4 = 32
Lets IMSI Value = x
Paging Group for a particular Mobile =
(x MOD 1000) MOD 32 where 32 is total Paging Groups.
e.g. if IMSI = 404685505601234
Paging Group = (404685505601234 MOD 1000)MOD32
i.e. => 234 MOD 32 => 10Paging Group = 10.
NONCOMBINED:
Total CCCH = 3
BS_AG_BLK_RES=1
So Channels reserved for Pagig = 31 = 2BS_PA_MFRMS=4
So total Paging groups = 2*4 = 8Paging Group = (IMSI MOD 1000)MOD 8
e.g
404685505601234 MOD 1000 MOD 8
=> 234 MOD 8 = 2
Paging Group = 2I hope this answers your query

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