SS7 link load This topic has 6 replies, 1 voice, and was last updated 9 years, 8 months ago by Amar_GSM. Viewing 7 posts - 1 through 7 (of 7 total) Author Posts 28th August 2006 at 05:46 #45671 ZeeshanGuest Can any one tell me what parametres do I need to calculate the SS7 link load? 8th September 2006 at 19:24 #45672 HocineGuest Hi, you should take in consideration number of message sent and received between nodes that you want to calculate C7 load 10th September 2006 at 10:03 #45673 SayedGuest Ok Hocine: I have the MSU in KBye in both direction ,send and recive for one hour ,can you now tell me how i can do the calculation. it is 200Kbye for one signalling link for one hour ,please do the calculation cheers 28th September 2006 at 05:51 #45674 KashifGuest Can you please tell how you calculated the total MSUs in one hour from both sides? 29th September 2006 at 19:50 #45675 FogersonGuest MSUs per second is an average of MSUs transmitted and received per link. RX and TX utilization is calculated based on bytes transmitted and the data rate of the link. MSU’s per second= (c7msutx + (c7msutx2 * 65536) + c7msurx + (c7msurx2 * 65536))/(Total Links in Service * 1800) 12th October 2006 at 19:27 #45676 KashifGuest once again thanks ,but i have some queries abt this formula. How can we know c7msutx and the other parameters mentioned? secondly what do you mean by 65536? what is 1800 in this? what is the difference between RX and RX 2? 26th March 2014 at 09:17 #45677 Amar_GSMGuest SS7 Link load= (Send Octat + Receive Octat)*8/64000/36000 1)Octat in Byte so multiply to 8. 2)n7LNK speed is 64Kbps so devide by 64000 3)measurement period 1 hours so multiply by 3600 to convert in seconds Author Posts Viewing 7 posts - 1 through 7 (of 7 total) The forum ‘Telecom Design’ is closed to new topics and replies.