yes, you are totally right. why did I say something so stupid ?
Maybe I meant to describe the case where the LACs are shared among several BSC… = the case where the size of the LAC doesn’t depend on the size of the BSC.
1 LAC is spread over several BSCs -> 1x pagings over n BSC.
2 LACs = 2x pagings.
Cheers (and thanks for the correction !!)