Example
If T = number of TRX in BSC
thus total TDMA time slot = Tx8
If GPRS traffic is 20% of this BSC
thus number of Packet switch(PS) = (Tx8)20/100
Suppose that T = 1000 TRx
Tx8 = 8000 , PS 20% = 1600 PS
For maximum MSC=MCS9 = 59.2Kbps
thus
Gb bandwidth = 1600×59.2Kbps = 94.72Mbps
any comment welcome